http://unibasil.livejournal.com/ (
unibasil.livejournal.com
) wrote
in
with_astronotus
2010-05-28 10:43 am (UTC)
no subject
Да, для n=3 косяк:
2
3*∫x^(-3)dx = 3*((2^(-2)/(-2) - (1^(-2)/(-2)) = 3 * (- ¼ /2 + ½) =
1
= 3 * ⅜ = 9/8
Главное же принцип, ведь так? ;))
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no subject
2
3*∫x^(-3)dx = 3*((2^(-2)/(-2) - (1^(-2)/(-2)) = 3 * (- ¼ /2 + ½) =
1
= 3 * ⅜ = 9/8
Главное же принцип, ведь так? ;))